Best posts made by Vinay Jaiswal
Latest posts made by Vinay Jaiswal
it is like, some other nuclei must be decay to form the required nuclei.
suppose we are talking about nuclei name B and it is formed by decay of nuclei A so it can be possible that the formation rate of B = decay rate of B
decay rate is (decay constantno. of nuclei at time t) as No is nuclei no. at t=0 but at any other time it will be different and suppose it is N.
so now rate of decay = rate of formation
@pranay-singh first, look at the basic concepts of p.e. and k.e.
the energy required to bring an electron from infinity to ground state is potential energy in ground state. it is -ve for attractive force. It is assumed that the p.e. is 0 at infinity. so the p.e. in ground state = -27.2 eV as per the above mentioned assumption.
k.e. in ground state = +13.6 eV
so total energy = -13.6 eV
Now, this question
it is not taking the above mentioned assumption that the p.e. is 0 at infinity.
total energy in 1st excited state = 23.8 eV
energy required for transition from n=1 to n=2 = 10.2 eV
total energy in ground state = 23.8-10.2 = 13.6 eV
k.e. in ground state = 13.6 eV
so p.e. in ground state = t.e. - k.e. = 0
k.e. in ground state will always same as velocity will always be same.
energy required for transition from any state to other is fixed for each level.
p.e. depends on the assumption that at which point we are taking the 0 level p.e.