@just_neelansh said in Reputation points:
@saiyan-ash
do you want to overcome that 120 sec barrier for posting doubts??
YES
@just_neelansh said in Reputation points:
@saiyan-ash
do you want to overcome that 120 sec barrier for posting doubts??
YES
The best way to approach such a question is to keep in mind the fact that whenever a Period 2 element is involved (from N to F), H bonding is always possible. Next, remember that a highly electronegative element can also form H-bonding. Even Cl can form H bonds but those bonds are not as strong as those of F so we consider HF as our answer.
I want to get my reputation points >=3
please tell how do I do that
Please tell the website from where you got this question
The approach is awesome
https://upload.wikimedia.org/wikipedia/commons/thumb/0/0f/Iodoform_synthesis.svg/450px-Iodoform_synthesis.svg.png
Answer (c) and (d) both are correct but (d) is most suitable since we do not need the yellow CHI3 compound for our conversion of Butan-2-one to propanoic acid but we need the I- ion to form CHI3- anion and remove the methyl group. NaI generates I- more easily than I2. Hence the given answer is (d)
The answer is indeed not (b). Both answers (a) and (d) are correct. But answer (d) is the most suitable since the question is asking for decreasing and not increasing order.
$U=10(1−COS6X)$
$F=−dU/dx$
$=−60sin6x$
as x is very small
$sin6x=6x$
Then, $F=−60(6x)$
$=−360x$
OR $ma=−360x$
OR $a=−360x$
Since, the oscillation are simple harmonic
$w_{2}=360$
OR $4pi_{2}/T_{2}=360$
OR $T=1/3$
If we read the question very carefully, it says when it is expanded to 200 litres at 2 atm pressure. This means that the applied external pressure is 2 atm. So it is written that Pext=2 atm.
It is written constant pressure because the pressure does not change in an isobaric process. This is a case of isobaric process.
The external pressure need change to 2 atm since 2 atm pressure is being applied. We are concerned with the change in internal energy which can be found out by calculating the work done. Work done in an isobaric process depends only on the change in volume and the external pressure applied.
@ayush_nath Yes I think you are absolutely right. No there might be a mistake in the question itself. $f(x+2pi/3)$ gives the same function. So it should be fundamental period. Thanks for your cooperation
@ashish-deo-singh I do not think there is a mistake in this question. This is from Cengage Functions