Work energy and power



  • 0_1546198224165_20181231_005926.jpg
    M is dropped freely from a height h.

    In this case how is mgh + mgx = kx^2/2 ??



  • @sarah-khan assume that block has zero potential energy at the level of spring when it is in natural length. so initially potential energy is mgh. this gets converted to pot nrg of spring and block. finally block has pot energy -mgx and spring has pot nrg (1/2)kx^2.
    now assuming block has final velocity zero then by conserving energy:
    mgh=-mgx+(1/2)kx^2


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