PNC


@harshalgajendra
Case 1:
4 distinct letters Permutation = 8C4 × 4!
Case 2:
2 same 2 distinct letters Permutation = 2C1 × 7C2 × 4!
Case 3:
2 same & 2 same letters Permutation = 4! / 2!×2!
Total no of ways = case 1+ case 2+ case 3
Answer = 1680 + 510 + 6 = 2190