Gaseous state



  • 0_1573273475580_20191109_095404.jpg b(6)
    Ans(a): 1.98%
    (B): 10.156 litres
    Please give explaination



  • @vikram-ghotra

    T = 273.15 + 20 = 293.15 KP (N2) = P = 745 mm Hg P (Water) = 760 – 745 = 15 mm Hg

    Lets assume that the portion of nitrogen is Xn, then as per the concept of partial pressure,P(N2) = Xn x P = 745 / 760 = 0.98

    Hence, the percentage of mole = 98%Mass of water vapor = Increases in weight of drying agent = 0.15gP(water) = 15 mm Hg exerted by 0.15 g of water,

    then by formula

    V = nRT/P= [(0.15/18) x (8.205 x 10-2 x 293.15)]/(15/760)= 10.2 L


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