Mohd sabir Shaikh last edited by
@pratime-jaiswal F(O+) is greater than F(O-)
so now we need to see the behvr of derivative in neighbourhood of 0.
so f ‘ is postive
hence f is striclty increasing in (0-h, 0) and (0,0+h).
hence f is strictly increasing at x=0
@ashish-deo-singh acc to your solution ,f is increasing only but not strictly increasing,i.e, option b .But correct option is a
no f is strictly . by defination.