Increasing


@pratimejaiswal F(O+) is greater than F(O)

@pratimejaiswal
f’(0)=0.
so now we need to see the behvr of derivative in neighbourhood of 0.
f’ =3x^2
so f ‘ is postive
hence f is striclty increasing in (0h, 0) and (0,0+h).
hence f is strictly increasing at x=0

@ashishdeosingh acc to your solution ,f is increasing only but not strictly increasing,i.e, option b .But correct option is a

@pratimejaiswal
no f is strictly . by defination.