Capacitance



  • 0_1568116537111_1568116500667184643731.jpg Q15 ans: (a) 50/3 uV at each point
    (b) zero



  • @science-club
    0_1568116807164_IMG_20190910_172941.jpg

    (a) Capacitor = (4 x 8)/(4 + 8) = 8/3μ and 6 x 3/6 x 3 = 2μF (i) The charge on the capacitance 8/3μF

    ∴ Q = 8/3 x 50 = 400/3

    ∴ The potential at 4μF = 400/3 x 4 = 100/3 at 8μF = 400/3 x 8 = 100/6 The Potential difference = 100/3 - 100/6 = 50μV

    (ii) Hence the effective charge at 2μF = 50 × 2 = 100μF ∴ Potential at 3μF =100/3;

    Potential at 6μF = 100/6

    ∴ Difference = 100/3 - 100/6 = 50/3μV

    ∴ The potential at C & D is 50/3μV

    (b) ∴ p/q = R/S = 1/2 = 1/2 = it It is balanced. So from it is cleared that the wheat star bridge balanced. So the potential at the point C & D are same.

    So no current flow through the point C & D. So if we connect another capacitor at the point C & D the charge on the capacitor is zero



  • @yash-kapoor the potential difference of upper two capacitors us 50uV so how is the potential at point C 50/3 uV


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