# EMI

• Ans is b

• @harshal eq resistance across inductor is $R/2$
and at t--->infinity current in circuit will be $E/R$
So current thru inductor at time t will be given by:

$I=\frac{E}{R}(1-e^{-tR/2L})$

Hence

$LdI/dt=\frac{E}{2}e^{-tR/2L}$

When $LdI/dt=E/4$

$tR/2L=ln2$

Hence $t=(L/R)(2ln2)=(L/R)ln4$

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