Harshal Patil last edited by Harshal Patil
@yashingle in a, hydride shift wont take place so after elimination of -OH the molecule will hav chiral centre at topmost carbon. So since elimination can occur at either left or right side, racemic mixture will be formed
In b, double bond will be formed b/w middle 2 carbons so number of alpha H will be 8
In c, carbocation cannot be formed at bridgehead posn so no dehydration
In d, there is no H for double bond to be formed at middle so elimination will occur at sideways posn amd number of alpha H will be 4.