Redox

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@ayush_nath n factor for AO4 is 52=3
n factor for (FeS)n is n(4(2))=6nequating number of equivalents:
0.01x6n=3x0.06
so n=3

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@harshalpatil is it (FeS)n or FeSn?

@ayush_nath i think it shud be (FeS)n

@harshalpatil ok i get it now