anag last edited by
Why can't option d be the answer? There is no methyl group here. Please explain.
Harshal Patil last edited by
attacks on oxygen forming a +ve charge on it.
Since there is no 3 degree or benzyllic carbon attached the mechanism will be SN2 (otherwise carbocation is formed and iodide is formed there). So
attacks where hindrance is less. In dis case it attacks on ethyl side.