A

@tanishq-yadav
For a bowler, average = runs knocked off / number of wickets taken
Suppose, before the last match, number of wickets taken = N
In the last match, number of wickets added (n) = 3
Therefore original average of the bowler = 200 / N
Total runs knocked off in the last match is given by ,
Sa = n x A + ∆A ( N + n)
Or, 52 = 3 x 200/N + (+1) x (N + 3) [ Since change in average ∆A = +1 ]
Or, N = 25 or 24.
Therefore, New average = 200 + 52 / 25 + 3 or 200 + 52 / 24 + 3
Therefore new average of bowler = 9 or 28/3.