RIDDHI SHAH
@RIDDHI SHAH
Best posts made by RIDDHI SHAH

RE: Com
You don’t need the value of e. This can be solved with basic laws of motion.

RE: Kinematics
@KhushiPathak
Vertical velocity of the ball =10sinθ=6
Horizontal velocity of the ball =10cosθ=8
Horizontal distance covered by the ball =2y
Time taken by the ball to reach man's hand
=2 u_vertical/g
=1.2s
⇒2y=8×1.2
⇒y=4.8mDistance travelled by the wall when ball hits wall =10−4.8=5.2m
u= velocity of the wall = 5.2/1.2=13/3
Latest posts made by RIDDHI SHAH

RE: NLM
@YouKnowwhere if you imagine that the rope is cut at x the only force on that part of the rope is T at x and that part has an acceleration a. So T must be ma

RE: Electrostatics
@YouKnowwhere you just need to keep the value of z=0 for zx plane. That’s an eqn of a circle.
Similarly you can solve the other bit. 
RE: RC circuit
B is obviously wrong because it is not satisfying the initial condition

RE: Kinematics
@KhushiPathak
Vertical velocity of the ball =10sinθ=6
Horizontal velocity of the ball =10cosθ=8
Horizontal distance covered by the ball =2y
Time taken by the ball to reach man's hand
=2 u_vertical/g
=1.2s
⇒2y=8×1.2
⇒y=4.8mDistance travelled by the wall when ball hits wall =10−4.8=5.2m
u= velocity of the wall = 5.2/1.2=13/3