Please explain how to solve this question. Please show working. This is my attempt:
Harshal Patil last edited by Harshal Patil
In first step PhCH(Cl)(CH3) is formed
In 2nd step there will be SN2 rxn and instead of -Cl,
-OH grp will come.
After oxidn with pcc, -OH becomes ketone grp.
So PhCOCH3 is correct option.
Cl2/hv is halogenation rxn in alkanes... it follows free radical mech.