Image



  • 0_1554129457108_Screenshot Capture - 2019-04-01 - 20-06-16.png
    ans - A
    i got the value but image will be formed on the left side of the lens in the focal plane
    so why it will be real?



  • @piyush-d

    ark the normal to the lens surface where the ray is incident.
    Calculate how much the ray bends as it enters the lens. Trace the ray to the back surface of the lens.
    Draw the normal to the exit surface where the ray is incident. Calculate how much the ray bends as it exits the lens.
    Trace the ray till the focal length.
    Three rays are usually taken to decide point of convergence - from the object top, object center and object bottom. So repeat the previous steps accordingly.
    When the parallel beam is parallel to the principle axis, we learn that the rays will converge at the designed focal length of the lens based on its refractive index and curvature.

    0_1554148657935_021CEEDD-C91E-4177-B61F-8C4CC18F9724.png

    so value is f tanαtan \alphatanα, assuming same angle as small angle of incidence.



  • @nukita-puyol
    U have written point of convergence..
    Thats why virtual image
    But lens is diverging... So it should be real and in the focal plane of second focus of lens


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