urvashi last edited by
Plz explain last statement .
Suppose we have an amine which has 5 Carbon.
If we want an amine with 6 C.
We will somehow convert that amine into an alkyl bromide
and then treat the halide with NaCN, now a Cyanide will be formed which will have one extra C than the parent amine (Extra C from NaCN)
We can now again reduce this into amine and the amine we'll have will have one extra C than parent amine.
There may be other methods to bring out this sort of conversions, this is just an example.