• 0_1553967767387_IMG_20190330_231236.jpg
    Plz explain last statement .

  • Suppose we have an amine which has 5 Carbon.
    If we want an amine with 6 C.
    We will somehow convert that amine into an alkyl bromide
    and then treat the halide with NaCN, now a Cyanide will be formed which will have one extra C than the parent amine (Extra C from NaCN)
    We can now again reduce this into amine and the amine we'll have will have one extra C than parent amine.
    There may be other methods to bring out this sort of conversions, this is just an example.

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