Circles

ansd
Please show working

@ayush_nath
Note :
The distance between Centre (g,f) nad the Vertex (1,1) = RIn equilateral Triangle r=R/2
So Eqn of incircle is $(x+g)_{2}$ +$(y+f)_{2}$ =
$r_{2}$ = ($R_{2}$)/4 = 1/4 [ $(g+1)_{2}$+
$(f+1)_{2}$ ]Simplify this eqn.
You will get
4($x_{2}$+$y_{2}$)+8gx+8fy=(1g)(1+3g)+(1f)(1+3f)