# Thermodynamics

• a-iv Since the value of Kp>Q, the reaction has tendency to proceed forward towards products so the process is spontaneous
b-i The value of del G is less than RT lnQ or we can say the value of Kp<Q so the reaction has tendency to move in the backward direction towards the reactants
c-ii The reaction is at equilibrium when Kp=Q The rate of forward reaction=Rate of backward reaction
d-iii From del G = del H - T delS, putting the value of T as T>delH/delS. So as both del H and del G are negative, the reaction is exothermic and spontaneous

• @goku thanks