Thermodynamics



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  • a-iv Since the value of Kp>Q, the reaction has tendency to proceed forward towards products so the process is spontaneous
    b-i The value of del G is less than RT lnQ or we can say the value of Kp<Q so the reaction has tendency to move in the backward direction towards the reactants
    c-ii The reaction is at equilibrium when Kp=Q The rate of forward reaction=Rate of backward reaction
    d-iii From del G = del H - T delS, putting the value of T as T>delH/delS. So as both del H and del G are negative, the reaction is exothermic and spontaneous



  • @goku thanks


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