Real gas


Given,
Density of water vapour=133.2gm/L
Pressure=327.6atm
Temperature=776.4K
Now we know,Ideal gas law
PV=nRT
Molar volume=n/V=P/RT
n/V=327.6/(0.0831*776.4)
=5.0775mol/L
Molar volume of real gas given calculation:
We know,1 mole water gas=18g
133.2g water gas=133.2/18=7.4 mole
Actual volume of given gas=7.4mol/L
Now we know,
Z=actual volume of real gas/volume for ideal gas
Z=7.4/5/0775=1.457

@YashKapoor thank you so much 🙏