Ans is marked
How to compare II and III?
king kong last edited by
@Mohan-Bhargav in 3rd option it is attached to phenyl group which shows -i effect therefore it will have acidic character therefore it will have least basic character
Mohan Bhargav last edited by Mohan Bhargav
@king-kong why can't we check resonance? In 3rd option there is cross conjugation due to phenyl group and NH2. SO lone pair of NH2 should be delocalised to lesser extent and hence lone pair will remain on N longer than in 2nd option and hence it is more basic than 2nd compound.
So shouldn't answer be 1> 3>2?
Please explain the flaw in my explanation.
@Mohan-Bhargav somebody, please solve my doubt
VEDANT ZOPE last edited by
@Mohan-Bhargav there is phenyl so there will be more conjugation so lone pair is not present on N
@VEDANT-ZOPE but NH 2 is in conjugation with CO na not with phenyl... Due to cross conjugation shouldn't resonance of NH2 with CO reduce and hence lone pair stay longer on N?
Sanjeev Patel last edited by
@Mohan-Bhargav here while comparing b/w 2 and 3... Both effects operate.. 1)inductive effect by phenyl grp which favors acetamide to be more basic ... 2)mesomeric(cross conjugation) which favors benzamide to be more basic.... So both contradicts each other... So we hv to go with experimental value.. Which says that acetamide is more basic if we compare.. Remember this