inverse trigo

if the range of (sin^1 +cos^1+tan^1 ) is (m,n) then find the value of m+n
ans pi.......

@kingkong sin^1(x) +cos^1(x)+tan^1(x) = π/2+tan^1(x)
now tan^1(x) is an increasing function, and its range is (π/2,π/2)
but the domain of the function is (1,1)
therefore range of π/2 + tan^1(x) = (π/2+ tan^1(1),π/2+ tan^1(1))
hence (π/4,3π/4).
therefore, π/4+3π/4=π

@SevenThree said in inverse trigo:
@kingkong sin^1(x) +cos^1(x)+tan^1(x) = π/2+tan^1(x)
now tan^1(x) is an increasing function, and its range is (π/2,π/2)
but the domain of the function is (1,1)
therefore range of π/2 + tan^1(x) = (π/2+ tan^1(1),π/2+ tan^1(1))
hence (π/4,3π/4).
therefore, π/4+3π/4=πMY EARLIER SOLUTION WAS WRONG AS I DID NOT CONSIDER THE DOMAIN OF THE FUNCTION.

@SevenThree ok thanks