Kinematics


@KhushiPathak
Vertical velocity of the ball =10sinθ=6
Horizontal velocity of the ball =10cosθ=8
Horizontal distance covered by the ball =2y
Time taken by the ball to reach man's hand
=2 u_vertical/g
=1.2s
⇒2y=8×1.2
⇒y=4.8mDistance travelled by the wall when ball hits wall =10−4.8=5.2m
u= velocity of the wall = 5.2/1.2=13/3