D&F BLOCK



  • photo_2020-06-05_20-51-47.jpg

    Q7-ANS-A

    PLS PROVIDE SOME WAY TO DETERMINE PRODUCT HERE.



  • @ABCDMA-ABCDMA Well it depends on the concentration of the HCl.

    At low concentrations, HCl completely ionises as it reacts with water to form aqueous H 3 O + and Cl- ions;-

    HCl(g) + H 2 O(l) → H 3 O + (aq) + Cl − (aq)

    CuCl 2 also ionises in aqueous solution to form Cu+2 and Cl- ions;-

    CuCl 2 (s) → Cu +2 (aq) + 2 Cl − (aq)

    However, at very high concentrations of HCl, a significant amount of unionised HCl is present. This reacts with dissolved Cu +2 ions to form the complex anion; tetrachlorocopper(II) (CuCl −24 );-

    Cu +2 (aq) + 4 HCl → CuCl −24 + 4H + (aq)


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