AOD

ANS NOT KNOWN

@ABCDMAABCDMA
Answer should be option A,B,C and D. Hope you understand it.


@ShwetaSwapnilSinha WHY DID U REJECT THE VE VE CASE?

@ABCDMAABCDMA
How is it possible?

@ShwetaSwapnilSinha WHY SHOULD F" BE ALWAYS +VE OR ALWAYS VE? CAN IT CHANGE SIGNS IN BETWEEN, EVEN THEN F' WOULD BE CONTINUOUS NA?

@ShwetaSwapnilSinha @KanishkKumar0 I MEAN WHY DID U TAKE 2 CASES FOR ALL X >0?
CANT THE 2 CASES SWITCH AS X VARIES?
CANT THE GRAPH BE LIKE THIS?
@KanishkKumar0 @ShwetaSwapnilSinha ?

@ABCDMAABCDMA If it is negative then f"(X) is negative then f'(X) is decreasing function means f'(X) is negative therefore f(X) is also decreasing means f(1)<f(0) that is f(1)<1 then also all the four options will be the answer.
For always positive it is coming less than equal to 4/3 then for sometimes f"(X) negative and positive then it will already be less than 4/3 as for always positive it is increasing then also less than 4/3 then for negative cases or any other cases the graph will be less than the always increasing graph therefore it will also be less than 4/3 then also all the four options are coming as answer.
The above graph you had made it is always less than 1 then also all the four options are the answer.
Hope you understand it.