Sanjeev Patel last edited by Sanjeev Patel
Sanket Biradar last edited by ashish deo singh
When f(a)=3 hai then f'(a)^2=77......graph bounded so it has to decrease. Also it has to increase to come 77 so. Hence in between 0 se 77. All values 1,2 .....76 will be taken
Sanjeev Patel last edited by
@Sanket-Biradar I'm unable to follow.. Can u give any example.. Of what is happening... F(x) is bounded b/w - 3 to 3..then how come f'2 is taking value from 1 to 76
Since F is bounded so it will not cross bounds of -3 to 3.
Now we have a point whr (f’ )^2 is 77. So obviously
It must risen to it from some value, also function will come down, so it will take values 1,2,,,,,76