VEDANT ZOPE last edited by VEDANT ZOPE
It is possible only at max value of quadratic so x will be -b/2a for quadratic 1 and y will be -b/2a for quadratic 2
X comes out to be -1/3 and y as 1/2 add them you will get answer as 6
@VEDANT-ZOPE why at max, not other multiples ?
VEDANT ZOPE last edited by
As of quadratic is concerned when 2 variables are involved we cannot solve them properly so we generally look for max or min value