Quadratic

Q5

@AlfaazSharma
It is possible only at max value of quadratic so x will be b/2a for quadratic 1 and y will be b/2a for quadratic 2
X comes out to be 1/3 and y as 1/2 add them you will get answer as 6

@VEDANTZOPE why at max, not other multiples ?

@AlfaazSharma
As of quadratic is concerned when 2 variables are involved we cannot solve them properly so we generally look for max or min value