Decreasing increasing


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@100miles here x ε [0,1]
But not valid for x>3

@100miles
you cant assume function.

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@PratimeJaiswal
f(x)f’(x)<0
multiply by $e_{−x}$
so its derivatatve of h(x)=$e_{−x}f(x)$ which is less than 0 so h is decreasing. so h(x)>h(0)

@KanishkKumar0
wrong. given condition for same x

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here y=f(x) and if f(x)>e^x then f(x) can never be equal to 0