Capacitor



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  • @ankita-maurya

    After 2.3  time constant does the energy of capacitor becomes 1/10 of its initial value

    Explanation :

    The discharging equation of a capacitor is given by,

    Q = Q₀e^(-t/T)

    where,

    Q₀ = initial charge

    T = Time constant

    Q = charge at time t = Q₀/10

    putting these values in the above equation we get,

    Q₀/10 = Q₀e^(-t/T)

    => e^(-t/T) = 1/10 = 0.1

    taking log on both the sides

    lne^(-t/T) = ln 0.1

    => (-t/T) = -2.3

    => t = 2.3T

    Hence after 2.3  time constant does the energy of capacitor becomes 1/10 of its initial value


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