What is the nfactor of NH3
@krish-kuppuram here nfactor of nh3 is asked
@siddhartha-ghosh pls somebody give explanation for nf of NH3
he has given you n factor of N atom. each N of ammonia is going from -3 to 0 so per mole ammonia transaction of electron is 3 . which is n factor for this reaction.
if NH3 was going just acid base reaction, then it accepts on H+ then it becomes 1.
@nukita-puyol ok thanks
We have to calculate nf for per mole right?
Oxidation state of N in N2 =0
Oxidation state of N in NH3 =-3
change in oxidation number of N in N2 in formation of NH3 =3
For 2 N atom = 6
So equivalent weight of N2 =28/6=14/3 g(molecular weight of N2 =28 g)
Equivalent weight of NH3= 17/3 g (molecular weight of NH3 =17 g)
Oxidation number change in H is =1 ( from 0 to +1)
so for two H atom in H2 =2
It means, equivalent weight of H2 = 2/1=2 g